Kayode - Maths tutor - Port Harcourt
1st lesson free
Kayode - Maths tutor - Port Harcourt

Kayode profile and its contact details have been verified by our experts

Kayode

  • Rate R61
  • Response 24h
  • Students

    Number of students Kayode has accompanied since joining Superprof

    1

    Number of students Kayode has accompanied since joining Superprof

Kayode - Maths tutor - Port Harcourt
  • 5 (2 reviews)

R61/h

1st lesson free

Contact

1st lesson free

1st lesson free

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Maths Logic

A dynamic and proficient Math tutor, incorporating sound knowledge of Engineering and Science to solving your mathematical problems. I teach the "understanding" of Math to aid your strength in not j

  • Maths
  • Trigonometry
  • Arithmetic
  • Geometry
  • Maths Logic

Lesson location

Recommended

Kayode is a respected tutor in our community. He is highly recommended for his commitment and the quality of his lessons. A trusted partner on your learning journey.

About Kayode

I am a Civil Engineer but I've been passionate about teaching. I presently take home lessons and online tutorials in some other platforms. I engage the teaching of basic principle of mathematics and engineering to expose students to the concept behind each Mathematical problem and hence stir up your interest in not just the questions but the topic as a whole. Once you get the understanding of Mathematics, you can easily solve any question even beyond the scope of the particular question.

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About the lesson

  • Primary
  • Secondary
  • Matric/GCSE
  • +8
  • levels :

    Primary

    Secondary

    Matric/GCSE

    AS Level

    A Level

    Adult education

    Undergraduate

    Masters

    Diploma

    Doctorate

    MBA

  • English

Languages in which the lesson is available :

English

Find the largest of three consecutive odd numbers whose sum is 57. Solution: Let the largest be x Consecutive odd numbers increase/decrease by difference of 2. This implies, other two numbers are (x-2) and (x-4) So, the sum; x + (x-2) + (x-4) = 57 Hence, solving, we have; 3x - 6= 57 Add 6 to both sides, 3x = 63 Dividing both sides by 3 X = 21. This implies that, the largest number is 21. Other two numbers are; X-2 => 21-2 = 19 X-4 => 21-4 = 17 Check: The sum = 21+19+17= 57

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Rates

Rate

  • R61

Package rates

  • 5h: R304
  • 10h: R608

online

  • R-6/h

free lesson

The free first lesson with Kayode allows you to get to know the tutor and discuss your needs and expectations.

  • 30min

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